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A heavy brass sphere is hung from a spiral spring and it execu

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A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period $T$ . the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be

Name: Video solution 1: A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period T. the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be
Uploaded: 2022-03-27T05:40:21.000Z
Duration: 6 min
Description: Video solution 1: A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period T. the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be

[\frac{9}{10}] T

T (\frac{10}{9})

u n c han g e d

T (\frac{9}{10})

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Updated on: Mar 27, 2022

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Alexander Discussed

A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period

T

. the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be

12 mins ago

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12 mins ago

Text solutionVerified

As the brass ball is always immersed in the non-viscous liquid the buoyant force will always be actively applied on it
Then,

F_{B} = ρ_{nvf} \cdot V g

, where

ρ_{nvf} =

density of non-viscous fluid

ρ_{nvf} = \frac{ρ _{b}}{10} (ρ_{b} =

density of brass;

m =

mass of brass ball

)

F_{B} = \frac{ρ _{b}}{10} (\frac{m}{ρ _{b}}) g \Rightarrow F_{B} = \frac{m g}{10}

Accordingly the effective downward force on the ball is

F_{eff} = m g - \frac{m g}{10}

i.e., weight

=

buoyant force

F_{eff} = m (g - \frac{g}{10}) = m (\frac{g}{10}) = m g_{eff} \Rightarrow g_{eff} = \frac{9 g}{10}

As we know new time period will be

T^{'} = 2 π \frac{1}{g _{eff}} = 2 π \frac{110}{9 g} = \frac{10}{9} (2 π \frac{1}{g}) = \frac{10}{9} T

T^{'} = \frac{10}{9} T

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Question Text	A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period $T$ . the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be
Updated On	Mar 27, 2022
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	234
Avg. Video Duration	6 min

A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period $T$ . the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be

Text solutionVerified

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A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period T. the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be

Text solutionVerified

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A heavy brass sphere is hung from a spiral spring and it executes vertical vibration with period $T$ . the ball is now immersed in non-viscous liquid with a density one-tenth that of brass. when set into vertical vibration with the sphere remaining inside the liquid all the time, the period will be