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Medium
Solving time: 3 mins
A convex lens has refractive index of 1.6. The radius of curvature of its front surface is and that of its back surface is . What is the power of the lens?
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Text solutionVerified
Using lens maker formula, we have
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Question 3
Determine the magnitude, direction, and sense of the resultant and equilibrant forces acting on the cross bracket shown below and the perpendicular distance of their line of action from the point W.
8 kN
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N.B. Not to scale
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WORKING PAGE
Perpendicular distance of
Perpendicular distance of
Moment about A, due to F = F * u * distance of F from pivot
Moment about A, due to Fv = F * y * distance of Fy from pivot
Force Angle [BN]
Horizontal component Vertical component of force F, of force F, F = F * cosθ Fv = F * sinθ
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[KNm]
F =
IFv =
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Mrv =
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Question Text | A convex lens has refractive index of 1.6. The radius of curvature of its front surface is and that of its back surface is . What is the power of the lens? |
Topic | Ray Optics and Optical Instruments |
Subject | Physics |
Class | Class 12 |
Answer Type | Text solution:1 |
Upvotes | 53 |