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Physics Part-I

Laws of motion

A constant retarding force of 50 N is applied to a body of mas

Physics Part-I

Class 11

NCERT

Chapter 1: Physical World

16 questions

Chapter 2: Units and Measurements

51 questions

Chapter 3: Motion in Straight Line

50 questions

Chapter 4: Motion in a Plane

43 questions

Chapter 5: Laws of motion

52 questions

One end of a string of length

l

is connected to a particle of mass

m

and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed

v

the net force on the particle ( directed towards the centre ) is :

A constant retarding force of

50

N

is applied to a body of mass

20

k g

moving initially with a speed of

15

m s^{- 1}

. How long does the body take to stop?

A constant force acting on a body of mass

3.0 k g

changes its speed from

2.0 m

s^{- 1}

3.5 m

s^{- 1}

25 s

. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

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Chapter 6: Work, Energy and Power

41 questions

Chapter 7: System of Particles and Rotational Motion

45 questions

Chapter 8: Gravitation

33 questions

Question

Easy

Solving time: 1 mins

A constant retarding force of $50$ $N$ is applied to a body of mass $20$ $k g$ moving initially with a speed of $15$ $m s^{- 1}$ . How long does the body take to stop?

Views: 6,082 students

Updated on: Feb 21, 2024

Book:

Physics Part-I (NCERT)

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Alexander Discussed

A constant retarding force of

50

N

is applied to a body of mass

20

k g

moving initially with a speed of

15

m s^{- 1}

. How long does the body take to stop?

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

Retarding force,

F = 50 N

Mass of the body,

m = 20 k g

Initial velocity of the body,

u = 15 m / s

Final velocity of the body,

v = 0

Using Newtons second law of motion, the acceleration (

a

) produced is given by:

F = ma

50 = 20

\times a

a = - 50/20 = - 2.5 m / s

^{2}

Using the first equation of motion, the time (

t

) taken by the body to come at rest

v = u + a t

t = - u / a = - 15/ - 2.5 = 6 s

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Practice more questions from Physics Part-I (NCERT)

One end of a string of length

l

is connected to a particle of mass

m

and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed

v

the net force on the particle ( directed towards the centre ) is :

A constant retarding force of

50

N

is applied to a body of mass

20

k g

moving initially with a speed of

15

m s^{- 1}

. How long does the body take to stop?

A constant force acting on a body of mass

3.0 k g

changes its speed from

2.0 m

s^{- 1}

3.5 m

s^{- 1}

25 s

. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

View all

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Question Text	A constant retarding force of $50$ $N$ is applied to a body of mass $20$ $k g$ moving initially with a speed of $15$ $m s^{- 1}$ . How long does the body take to stop?
Updated On	Feb 21, 2024
Topic	Laws of motion
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 28
Upvotes	3049
Avg. Video Duration	4 min

A constant retarding force of $50$ $N$ is applied to a body of mass $20$ $k g$ moving initially with a speed of $15$ $m s^{- 1}$ . How long does the body take to stop?

Text solutionVerified

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