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Physics Part-I

Laws of motion

A constant force acting on a body of mass 3.0 kg changes its s

Physics Part-I

Class 11

NCERT

Chapter 1: Physical World

16 questions

Chapter 2: Units and Measurements

51 questions

Chapter 3: Motion in Straight Line

50 questions

Chapter 4: Motion in a Plane

43 questions

Chapter 5: Laws of motion

52 questions

A constant retarding force of

50

N

is applied to a body of mass

20

k g

moving initially with a speed of

15

m s^{- 1}

. How long does the body take to stop?

A constant force acting on a body of mass

3.0 k g

changes its speed from

2.0 m

s^{- 1}

3.5 m

s^{- 1}

25 s

. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

A body of mass

5 k g

is acted upon by two perpendicular forces

8 N

and

6 N

.Give the magnitude and direction of the acceleration of the body.

View all question

Chapter 6: Work, Energy and Power

41 questions

Chapter 7: System of Particles and Rotational Motion

45 questions

Chapter 8: Gravitation

33 questions

Question

Easy

Solving time: 1 mins

A constant force acting on a body of mass $3.0 k g$ changes its speed from $2.0 m$ $s^{- 1}$ to $3.5 m$ $s^{- 1}$ in $25 s$ . The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

Views: 5,885 students

Updated on: Jul 14, 2023

Book:

Physics Part-I (NCERT)

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Sebastian Discussed

A constant force acting on a body of mass

3.0 k g

changes its speed from

2.0 m

s^{- 1}

3.5 m

s^{- 1}

25 s

. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

Mass of the body, m = 3 kg
Initial speed of the body, u = 2 m/s
Final speed of the body, v = 3.5 m/s
Time, t = 25 s

Using the first equation of motion, the acceleration (

a

) produced in the body can be calculated as:

v = u + a t

a = \frac{( v - u )}{t}

= \frac{( 3.5 - 2 )}{25} = 0.06 m

/ s^{2}

As per Newton's second law of motion, force is given as:

F = ma

= 3 \times 0.06 = 0.18 N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

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Practice more questions from Physics Part-I (NCERT)

A constant retarding force of

50

N

is applied to a body of mass

20

k g

moving initially with a speed of

15

m s^{- 1}

. How long does the body take to stop?

A constant force acting on a body of mass

3.0 k g

changes its speed from

2.0 m

s^{- 1}

3.5 m

s^{- 1}

25 s

. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

A body of mass

5 k g

is acted upon by two perpendicular forces

8 N

and

6 N

.Give the magnitude and direction of the acceleration of the body.

View all

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Question Text	A constant force acting on a body of mass $3.0 k g$ changes its speed from $2.0 m$ $s^{- 1}$ to $3.5 m$ $s^{- 1}$ in $25 s$ . The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?
Updated On	Jul 14, 2023
Topic	Laws of motion
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 10
Upvotes	899
Avg. Video Duration	9 min

A constant force acting on a body of mass $3.0 k g$ changes its speed from $2.0 m$ $s^{- 1}$ to $3.5 m$ $s^{- 1}$ in $25 s$ . The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

Text solutionVerified

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A constant force acting on a body of mass $3.0 k g$ changes its speed from $2.0 m$ $s^{- 1}$ to $3.5 m$ $s^{- 1}$ in $25 s$ . The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?