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Projectile motion

A body is projected at time t=0 with a velocity u at an angle

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Solving time: 3 mins

A body is projected at time $t = 0$ with a velocity $u$ at an angle $θ$ with the horizontal. The horizontal and vertical components of its velocity will become equal at time $t \neq = 0$ ,

0 \leq θ \leq \frac{π}{4}

\frac{π}{4} \leq θ \leq \frac{π}{2}

0 \leq θ \leq \frac{π}{6}

for no value of

θ

Views: 5,575 students

Book:

IIT JEE Advanced Comprehensive Physics (McGraw Hill)

Found 4 tutors discussing this question

Henry Discussed

A body is projected at time

t = 0

with a velocity

u

at an angle

θ

with the horizontal. The horizontal and vertical components of its velocity will become equal at time

t \neq = 0

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

Horizontal component of velocity at a time

t

v_{r} = u cos θ

vertical component of velocity at that time

t

v_{y} = u sin θ - g t

They will become equal at time

t = t^{*}

u cos θ = u sin θ - g t^{*}

which gives

t^{*} = u (sin θ - cos θ)

Now

t^{*}

must be positive. Hence

sin θ > cos θ

θ > π /4

.
Hence the correct choice is (b).

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Question Text	A body is projected at time $t = 0$ with a velocity $u$ at an angle $θ$ with the horizontal. The horizontal and vertical components of its velocity will become equal at time $t \neq = 0$ ,
Topic	Motion in a Plane
Subject	Physics
Class	Class 11
Answer Type	Text solution:1
Upvotes	75

A body is projected at time $t = 0$ with a velocity $u$ at an angle $θ$ with the horizontal. The horizontal and vertical components of its velocity will become equal at time $t \neq = 0$ ,

Text solutionVerified

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A body is projected at time $t = 0$ with a velocity $u$ at an angle $θ$ with the horizontal. The horizontal and vertical components of its velocity will become equal at time $t \neq = 0$ ,