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Work energy theorem

A bead of mass {1}{2} {~kg} starts from rest from A to move in

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Medium

Solving time: 3 mins

A bead of mass $\frac{1}{2} kg$ starts from rest from $A$ to move in a vertical plane along a smooth fixed quarter ring of radius $5 m$ , under the action of a constant horizontal force $F = 5 N$ as shown. The speed of bead as it reaches the point $B$ is [Take $g = 10 ms^{- 2}$ ]

14.14 ms^{- 1}

7.07 ms^{- 1}

4 ms^{- 1}

25 ms^{- 1}

Views: 6,104 students

Updated on: Oct 25, 2023

Book:

Mechanics Volume 1 (DC Pandey)

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Olivia Discussed

A bead of mass

\frac{1}{2} kg

starts from rest from

A

to move in a vertical plane along a smooth fixed quarter ring of radius

5 m

, under the action of a constant horizontal force

F = 5 N

as shown. The speed of bead as it reaches the point

B

is [Take

g = 10 ms^{- 2}

]

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

W_{All} = \frac{1}{2} m v^{2}

∴ W_{F} + W_{m g} + W_{N} = \frac{1}{2} m v^{2}

∴ (5 \times 5) + (\frac{1}{2} \times 10 \times 5) + 0 = \frac{1}{2} \times \frac{1}{2} \times v^{2}

∴ v = 14.14 m / s

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Question Text	A bead of mass $\frac{1}{2} kg$ starts from rest from $A$ to move in a vertical plane along a smooth fixed quarter ring of radius $5 m$ , under the action of a constant horizontal force $F = 5 N$ as shown. The speed of bead as it reaches the point $B$ is [Take $g = 10 ms^{- 2}$ ]
Updated On	Oct 25, 2023
Topic	Work, Energy and Power
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 16
Upvotes	1625
Avg. Video Duration	7 min

A bead of mass $\frac{1}{2} kg$ starts from rest from $A$ to move in a vertical plane along a smooth fixed quarter ring of radius $5 m$ , under the action of a constant horizontal force $F = 5 N$ as shown. The speed of bead as it reaches the point $B$ is [Take $g = 10 ms^{- 2}$ ]

Text solutionVerified

Filo tutor solutions (16)

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A bead of mass 21​ kg starts from rest from A to move in a vertical plane along a smooth fixed quarter ring of radius 5 m, under the action of a constant horizontal force F=5 N as shown. The speed of bead as it reaches the point B is [Take g=10 ms−2 ]

Text solutionVerified

Filo tutor solutions (16)

Practice questions from Mechanics Volume 1 (DC Pandey)

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A bead of mass $\frac{1}{2} kg$ starts from rest from $A$ to move in a vertical plane along a smooth fixed quarter ring of radius $5 m$ , under the action of a constant horizontal force $F = 5 N$ as shown. The speed of bead as it reaches the point $B$ is [Take $g = 10 ms^{- 2}$ ]