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A ball of mass 'm' moving with a horizontal velocity 'v' strik

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A ball of mass 'm' moving with a horizontal velocity 'v' strikes the bob of mass 'm' of a pendulum at rest. During this collision, the ball sticks with the bob of the pendulum. The height to which the combined mass raises is (g = acceleration due to gravity).

\frac{v ^{2}}{4 g}

\frac{v ^{2}}{8 g}

\frac{v ^{2}}{g}

\frac{v ^{2}}{2 g}

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A ball of mass 'm' moving with a horizontal velocity 'v' strikes the bob of mass 'm' of a pendulum at rest. During this collision, the ball sticks with the bob of the pendulum. The height to which the combined mass raises is (g = acceleration due to gravity).

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Question Text	A ball of mass 'm' moving with a horizontal velocity 'v' strikes the bob of mass 'm' of a pendulum at rest. During this collision, the ball sticks with the bob of the pendulum. The height to which the combined mass raises is (g = acceleration due to gravity).
Answer Type	Video solution: 1
Upvotes	151