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Terminal velocity

A ball of mass m and radius r is released in the viscous liqui

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Medium

Solving time: 3 mins

A ball of mass m and radius r is released in the viscous liquid. The value of its terminal velocity is proportional to :

Name: Video solution 1: A ball of mass m and radius r is released in the viscous liquid. The value of its terminal velocity is proportional to :
Uploaded: 2022-11-04T04:30:28.000Z
Duration: 9 min
Description: Video solution 1: A ball of mass m and radius r is released in the viscous liquid. The value of its terminal velocity is proportional to :

(\frac{1}{r})

only

\frac{m}{r}

(\frac{m}{r})^{1/2}

m

only.

Views: 5,972 students

Updated on: Nov 4, 2022

Found 3 tutors discussing this question

Oliver Discussed

A ball of mass m and radius r is released in the viscous liquid. The value of its terminal velocity is proportional to :

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Text solutionVerified

Lets consider

m =

mass of a ball

r =

radius of a ball

v =

terminal velocity
By stocks law,
Viscous force

+

Buoyancy force

=

weight

6 π ηr v + \frac{4}{3} π r^{3} ρ g = m g

6 π η v r = m g - \frac{4}{3} π r^{3} ρ g

v = \frac{m g}{6 π ηr} - \frac{4 π r ^{3} ρ g}{18 π ηr}

. . . . . .(1)
If the density

ρ

is negligible, Equation (1) become,

v = \frac{m g}{6 π ηr}

v \propto \frac{m}{r}

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Question Text	A ball of mass m and radius r is released in the viscous liquid. The value of its terminal velocity is proportional to :
Updated On	Nov 4, 2022
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	170
Avg. Video Duration	9 min

A ball of mass m and radius r is released in the viscous liquid. The value of its terminal velocity is proportional to :

Text solutionVerified

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