Relations and Functions II
Write the following in logarithm form:5−2=251
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25log10x=5+4xlog105, solve for x.
If log(2a−b)=21(loga+logb), then the value of a2+b2−6ab is equal to
Given log10x=2a and log10y=2b. Write 10a in terms of x.
Solution of log(x2+6x+8)(log(2x2+2x+3)(x2−2x) )=0 is
Convert the following to logarithmic form:90=1
Convert the following into exponential form:log10(0.001)=−3
Solve the following equation:log2(100x)+log2(10x)=14+logx1
The value of log51 is