The value of ∣x∣→∞limcos(tan−1(sin(tan−1x))) is equal to

∣x∣→∞limcos(tan−1(sin(tan−1x)))=cos(tan−1(sin(tan−1∞)))=cos(tan−1(sin(2π))=cos(tan−1(1))=cos(4π)=21

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The value of {|x|}{lim}cos(tan^{-1}(sin(tan^{-1}x))) is equal

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The value of $∣ x ∣ \to \infty l im cos (t a n^{- 1} (s in (t a n^{- 1} x)))$ is equal to

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2

- \frac{1}{2}

\frac{1}{2}

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Alexander Discussed

The value of

∣ x ∣ \to \infty l im cos (t a n^{- 1} (s in (t a n^{- 1} x)))

is equal to

11 mins ago

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11 mins ago

∣ x ∣ \to \infty l im cos (t a n^{- 1} (s in (t a n^{- 1} x))) = cos (t a n^{- 1} (s in (t a n^{- 1} \infty)))

= cos (t a n^{- 1} (s in (\frac{π}{2}))

= cos (t a n^{- 1} (1))

= cos (\frac{π}{4}) = \frac{1}{2}

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Question Text	The value of $∣ x ∣ \to \infty l im cos (t a n^{- 1} (s in (t a n^{- 1} x)))$ is equal to
Answer Type	Text solution:1
Upvotes	150