The value of $sin (2 sin^{- 1} (0.6))$ is

0.48

0.96

1.2

sin 1.2

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Text solutionVerified

(B) is the correct answer.

Let

sin^{- 1} (0.6) = θ \Rightarrow sin θ = 0.6

∴ sin (2 sin^{- 1} (0.6)) = sin (2 θ) = 2 sin θ cos θ = 2 sin θ 1 - sin^{2} θ = 2 (0.6) (1 - 0.6^{2}) = 2 (0.6) (0.8) = 0.96

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