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The value of _{2-{3}}(2+{3})=-x. Then x is:

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The value of $lo g_{2 - 3} (2 + 3) = - x$ . Then $x$ is:

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The value of

lo g_{2 - 3} (2 + 3) = - x

. Then

x

is:

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Text solutionVerified

Let

- x = lo g_{(2 - 3)} (2 + 3)

\Rightarrow (2 - 3)^{- x} = 2 + 3

\Rightarrow (2 - 3)^{- x} = \frac{( 2 + 3 ) ( 2 - 3 )}{2 - 3} = (2 - 3)^{- 1}

\Rightarrow - x = - 1

∴ x = 1

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