The value of sec237−tan237sin253+cos253 is

Given, sec237−tan237sin253+cos253We know, sin2θ+cos2θ=1 and sec2θ−tan2θ=1∴sec237−tan237sin253+cos253=1

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The value of { ^{2}53+ ^{2}53}{ ^{2}37- ^{2}37 } is

Question

The value of $\frac{sin ^{2} 53 + cos ^{2} 53}{sec ^{2} 37 - tan ^{2} 37}$ is

1

2

\frac{1}{4}

\frac{3}{2}

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The value of

\frac{sin ^{2} 53 + cos ^{2} 53}{sec ^{2} 37 - tan ^{2} 37}

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Given,

\frac{sin ^{2} 53 + cos ^{2} 53}{sec ^{2} 37 - tan ^{2} 37}

We know,

sin^{2} θ + cos^{2} θ = 1

and

sec^{2} θ - tan^{2} θ = 1

∴ \frac{sin ^{2} 53 + cos ^{2} 53}{sec ^{2} 37 - tan ^{2} 37} = 1

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Question Text	The value of $\frac{sin ^{2} 53 + cos ^{2} 53}{sec ^{2} 37 - tan ^{2} 37}$ is
Answer Type	Text solution:1
Upvotes	150