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The tangent to the curve {y}={e}^{{x}} drawn at the point {({c

Question

The tangent to the curve $y = e^{x}$ drawn at the point $(c, e^{c})$ intersects the line joining $(c - 1, e^{c - 1}) and (c + 1, e^{c + 1})$ (a) on the left of $n = c$ (b) on the right of $n = c$ (c) at no points (d) at all points

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Theodore Discussed

The tangent to the curve

y = e^{x}

drawn at the point

(c, e^{c})

intersects the line joining

(c - 1, e^{c - 1}) and (c + 1, e^{c + 1})

(a) on the left of

n = c

(b) on the right of

n = c

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Question Text

The tangent to the curve

y = e^{x}

drawn at the point

(c, e^{c})

intersects the line joining

(c - 1, e^{c - 1}) and (c + 1, e^{c + 1})

(a) on the left of

n = c

(b) on the right of

n = c

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