The point on the curve $4 x^{2} + a^{2} y^{2} = 4 a^{2}$ ; $4 < a^{2} < 8$ that is farthest from the point (0,-2) is

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The point on the curve

4 x^{2} + a^{2} y^{2} = 4 a^{2}

;

4 < a^{2} < 8

that is farthest from the point (0,-2) is

11 mins ago

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Question Text

The point on the curve

4 x^{2} + a^{2} y^{2} = 4 a^{2}

;

4 < a^{2} < 8

that is farthest from the point (0,-2) is

Filo tutor solution