The multiplication inverse of $A = [cos θ sin θ - sin θ cos θ]$ is

[- cos θ - sin θ sin θ - cos θ]

[cos θ - sin θ sin θ cos θ]

[- cos θ sin θ - sin θ - cos θ]

[cos θ sin θ sin θ - cos θ]

Views: 766 students

Found 7 tutors discussing this question

Scarlett Discussed

The multiplication inverse of

A = [cos θ sin θ - sin θ cos θ]

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

$∣ A ∣ = cos^{2} θ + sin^{2} θ = 1$

$a d j (A) = [cos θ - sin θ sin θ cos θ]$

$A^{- 1} = \frac{a d j ( A )}{∣ A ∣} = [cos θ - sin θ sin θ cos θ]$

Was this solution helpful?

150

Report

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our maths tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	The multiplication inverse of $A = [cos θ sin θ - sin θ cos θ]$ is
Answer Type	Text solution:1
Upvotes	150