The logarithm of 27 to the base 9 is m3. Then the value of m is equal to

log927=m3 ...(1)Let log927=xConverting in exponential form,27=9x33=32xx=23 ...(2)Comparing equations (1) and (2), we getm=2

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The logarithm of 27 to the base 9 is {3}{m}. Then the value o

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The logarithm of $27$ to the base $9$ is $\frac{3}{m}$ . Then the value of $m$ is equal to

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The logarithm of

27

to the base

9

\frac{3}{m}

. Then the value of

m

is equal to

6 mins ago

Discuss this question LIVE

6 mins ago

lo g_{9} 27 = \frac{3}{m}

...(1)

Let

lo g_{9} 27 = x

Converting in exponential form,

27 = 9^{x}

3^{3} = 3^{2 x}

x = \frac{3}{2}

...(2)

Comparing equations (1) and (2), we get

m = 2

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Question Text	The logarithm of $27$ to the base $9$ is $\frac{3}{m}$ . Then the value of $m$ is equal to
Answer Type	Text solution:1
Upvotes	150