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The locus of the foot of perpendicular drawn from the centre o

Question

The locus of the foot of perpendicular drawn from the centre of the ellipse $x^{2} + 3 y^{2} = 6$ on any tangent to it is

(x^{2} - y^{2})^{2} = 6 x^{2} + 2 y^{2}

(x^{2} - y^{2})^{2} = 6 x^{2} - 2 y^{2}

(x^{2} + y^{2})^{2} = 6 x^{2} + 2 y^{2}

(x^{2} + y^{2})^{2} = 6 x^{2} - 2 y^{2}

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The locus of the foot of perpendicular drawn from the centre of the ellipse

x^{2} + 3 y^{2} = 6

on any tangent to it is

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Question Text	The locus of the foot of perpendicular drawn from the centre of the ellipse $x^{2} + 3 y^{2} = 6$ on any tangent to it is
Answer Type	Video solution: 1
Upvotes	150