The locus of the centre of the circle which bisects the circumferences of the circles $x^{2} + y^{2} = 4$ and $x^{2} + y^{2} - 2 x + 6 y + 1 = 0$ is

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The locus of the centre of the circle which bisects the circumferences of the circles

x^{2} + y^{2} = 4

and

x^{2} + y^{2} - 2 x + 6 y + 1 = 0

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Question Text

The locus of the centre of the circle which bisects the circumferences of the circles

x^{2} + y^{2} = 4

and

x^{2} + y^{2} - 2 x + 6 y + 1 = 0

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