The integral ∫24logx2+log(36−12x+x2)dxlogx2 is equal to:

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The integral $\int_{2}^{4} \frac{lo g x ^{2}}{lo g x ^{2} + lo g ( 36 - 12 x + x ^{2} ) d x}$ is equal to:

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The integral

\int_{2}^{4} \frac{lo g x ^{2}}{lo g x ^{2} + lo g ( 36 - 12 x + x ^{2} ) d x}

is equal to:

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Question Text	The integral $\int_{2}^{4} \frac{lo g x ^{2}}{lo g x ^{2} + lo g ( 36 - 12 x + x ^{2} ) d x}$ is equal to:
Answer Type	Video solution: 1
Upvotes	150