The image of the line 3x−1=1y−3=−5z−4in the plane 2x−y+z+3=0is the line

Name: Video solution 1: The image of the line 3x−1=1y−3=−5z−4in the plane 2x−y+z+3=0is the line
Uploaded: 2021-01-01T18:41:02.000Z
Duration: 2 min
Description: Video solution 1: The image of the line 3x−1=1y−3=−5z−4in the plane 2x−y+z+3=0is the line

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The image of the line {{{x}-{1}}}{{3}}={{{y}-{3}}}{{1}}={{{z}-

Question

The image of the line $\frac{x - 1}{3} = \frac{y - 3}{1} = \frac{z - 4}{- 5}$ in the plane $2 x - y + z + 3 = 0$ is the line

\frac{x + 3}{3} = \frac{y - 5}{1} = \frac{z - 2}{- 5}

\frac{x + 3}{- 3} = \frac{y - 5}{- 1} = \frac{z + 2}{5}

\frac{x - 3}{3} = \frac{y + 5}{1} = \frac{z - 2}{- 5}

(3)

\frac{x - 3}{- 3} = \frac{y + 5}{- 1} = \frac{z - 2}{5}

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Emma Discussed

The image of the line

\frac{x - 1}{3} = \frac{y - 3}{1} = \frac{z - 4}{- 5}

in the plane

2 x - y + z + 3 = 0

is the line

12 mins ago

Discuss this question LIVE

12 mins ago

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Question Text	The image of the line $\frac{x - 1}{3} = \frac{y - 3}{1} = \frac{z - 4}{- 5}$ in the plane $2 x - y + z + 3 = 0$ is the line
Answer Type	Video solution: 1
Upvotes	152

The image of the line 3x−1​=1y−3​=−5z−4​in the plane 2x−y+z+3=0is the line

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The image of the line $\frac{x - 1}{3} = \frac{y - 3}{1} = \frac{z - 4}{- 5}$ in the plane $2 x - y + z + 3 = 0$ is the line