The following integral ∫4π2π(2cosecx)17dxis equal to(a)∫0log(1+2)2(eu+e−u)16du(b)∫0log(1+2)2(eu+e−u)17du(c)∫0log(1+2)2(eu−e−u)17du(d)∫0log(1+2)2(eu−e−u)16du

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The following integral $\int_{\frac{π}{4}}^{\frac{π}{2}} (2 cos e c x)^{17} d x$ is equal to $(a) \int_{0}^{log (1 + 2)} 2 (e^{u} + e^{- u})^{16} d u$ $(b) \int_{0}^{log (1 + 2)} 2 (e^{u} + e^{- u})^{17} d u$ $(c) \int_{0}^{log (1 + 2)} 2 (e^{u} - e^{- u})^{17} d u$ $(d) \int_{0}^{log (1 + 2)} 2 (e^{u} - e^{- u})^{16} d u$

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The following integral

\int_{\frac{π}{4}}^{\frac{π}{2}} (2 cos e c x)^{17} d x

is equal to

(a) \int_{0}^{log (1 + 2)} 2 (e^{u} + e^{- u})^{16} d u

(b) \int_{0}^{log (1 + 2)} 2 (e^{u} + e^{- u})^{17} d u

(c) \int_{0}^{log (1 + 2)} 2 (e^{u} - e^{- u})^{17} d u

(d) \int_{0}^{log (1 + 2)} 2 (e^{u} - e^{- u})^{16} d u

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Question Text	The following integral $\int_{\frac{π}{4}}^{\frac{π}{2}} (2 cos e c x)^{17} d x$ is equal to $(a) \int_{0}^{log (1 + 2)} 2 (e^{u} + e^{- u})^{16} d u$ $(b) \int_{0}^{log (1 + 2)} 2 (e^{u} + e^{- u})^{17} d u$ $(c) \int_{0}^{log (1 + 2)} 2 (e^{u} - e^{- u})^{17} d u$ $(d) \int_{0}^{log (1 + 2)} 2 (e^{u} - e^{- u})^{16} d u$
Answer Type	Video solution: 1
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