The area bounded by y=3−∣3−x∣andy=∣x+1∣6 is

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The area bounded by {y}={3}-{|{3}-{x}|}{{and}}{y}={{{6}}}{{{|{

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The area bounded by $y = 3 - ∣ 3 - x ∣ and y = \frac{6}{∣ x + 1 ∣}$ is

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y = 3 - ∣ 3 - x ∣ and y = \frac{6}{∣ x + 1 ∣}

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Question Text

The area bounded by

y = 3 - ∣ 3 - x ∣ and y = \frac{6}{∣ x + 1 ∣}