tan−1y=tan−1x+tan−1(1−x22x) where ∣x∣<31. Then a value of y is:

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tan^{-1}y=tan^{-1}x+tan^{-1}({2x}{1-x^{2}}) where |x| < {1}{{3

Question

$t a n^{- 1} y = t a n^{- 1} x + t a n^{- 1} (\frac{2 x}{1 - x ^{2}})$ where $∣ x ∣ < \frac{1}{3}$ . Then a value of y is:

\frac{3 x + x ^{3}}{1 + 3 x ^{2}}

\frac{3 x - x ^{3}}{1 + 3 x ^{2}}

\frac{3 x + x ^{3}}{1 - 3 x ^{2}}

\frac{3 x - x ^{3}}{1 - 3 x ^{2}}

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Michael Discussed

t a n^{- 1} y = t a n^{- 1} x + t a n^{- 1} (\frac{2 x}{1 - x ^{2}})

where

∣ x ∣ < \frac{1}{3}

. Then a value of y is:

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Question Text

t a n^{- 1} y = t a n^{- 1} x + t a n^{- 1} (\frac{2 x}{1 - x ^{2}})

where

∣ x ∣ < \frac{1}{3}

. Then a value of y is: