Suppose that f(0)=0andf′(0)=2,and≤tg(x)=f(−x+f(f(x))). The value of g'(0) is equal to -

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Suppose that {f{{({0})}}}={0}{{and}}{f}'{({0})}={2},{{and}}{t}

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Suppose that $f (0) = 0 and f^{'} (0) = 2, and \leq t g (x) = f (- x + f (f (x))) .$ The value of g'(0) is equal to -

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Suppose that

f (0) = 0 and f^{'} (0) = 2, and \leq t g (x) = f (- x + f (f (x))) .

The value of g'(0) is equal to -

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Question Text

Suppose that

f (0) = 0 and f^{'} (0) = 2, and \leq t g (x) = f (- x + f (f (x))) .

The value of g'(0) is equal to -