Statement - I : The value of the integral ∫π/6π/31+tanxdxis equal to 6π.Statement - II : ∫abf(x)dx=∫abf(a+b−x)dx˙

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Statement - I : The value of the integral {_{{/{6}}}^{{/{3}}}}

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Statement - I : The value of the integral $\int_{π / 6}^{π / 3} \frac{d x}{1 + tan x}$ is equal to $\frac{π}{6}$ .Statement - II : $\int_{a}^{b} f (x) d x = \int_{a}^{b} f (a + b - x) d x ˙$

Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I

Statement -I is True; Statement -II is False.

Statement -I is False; Statement -II is True

Statement -I is True; Statement -II is True; Statement-II is a correct explanation for Statement-I

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Statement - I : The value of the integral

\int_{π / 6}^{π / 3} \frac{d x}{1 + tan x}

is equal to

\frac{π}{6}

.Statement - II :

\int_{a}^{b} f (x) d x = \int_{a}^{b} f (a + b - x) d x ˙

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Question Text	Statement - I : The value of the integral $\int_{π / 6}^{π / 3} \frac{d x}{1 + tan x}$ is equal to $\frac{π}{6}$ .Statement - II : $\int_{a}^{b} f (x) d x = \int_{a}^{b} f (a + b - x) d x ˙$
Answer Type	Video solution: 1
Upvotes	150