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V = 2 2 - 3 + + 3 r can be expressed as

Question

$lo g V = 2 lo g 2 - lo g 3 + lo g π + 3 lo g r$ can be expressed as

V = \frac{4}{3} π r^{3}

V = \frac{2}{3} π r^{3}

V = \frac{4}{3} π r

V = \frac{2}{3} π r

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Benjamin Discussed

lo g V = 2 lo g 2 - lo g 3 + lo g π + 3 lo g r

can be expressed as

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Text solutionVerified

lo g V = 2 lo g 2 - lo g 3 + lo g π + 3 lo g r

lo g V = lo g (2^{2} \times π \times r^{3}) - lo g 3

lo g V = lo g \frac{4 π r ^{3}}{3}

Removing log

V = \frac{4}{3} π r^{3}

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Question Text	$lo g V = 2 lo g 2 - lo g 3 + lo g π + 3 lo g r$ can be expressed as
Answer Type	Text solution:1
Upvotes	150