Let y=g(x) be the solution of the differential equation sinx(dxdy)+ycosx=4x,x∈(0,π) If y(2π)=0, then y(6π) is equal to

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Let {y}={g{{({x})}}} be the solution of the differential equat

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Let $y = g (x)$ be the solution of the differential equation $sin x (\frac{d y}{d x}) + y cos x = 4 x, x \in (0, π)$ If $y (\frac{π}{2}) = 0$ , then $y (\frac{π}{6})$ is equal to

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Let

y = g (x)

be the solution of the differential equation

sin x (\frac{d y}{d x}) + y cos x = 4 x, x \in (0, π)

y (\frac{π}{2}) = 0

, then

y (\frac{π}{6})

is equal to

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Question Text	Let $y = g (x)$ be the solution of the differential equation $sin x (\frac{d y}{d x}) + y cos x = 4 x, x \in (0, π)$ If $y (\frac{π}{2}) = 0$ , then $y (\frac{π}{6})$ is equal to
Answer Type	Video solution: 1
Upvotes	150