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Let P be the point on the parabola, {y}^{{2}}={8}{x}which is a

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Let P be the point on the parabola, $y^{2} = 8 x$ which is at a minimum distance from the centre C of the circle, $x^{2} + (y + 6)^{2} = 1 .$ Then the equation of the circle, passing through C and having its centre at P is :

x^{2} + y^{2} - 4 x + 8 y + 12 = 0

x^{2} + y^{2} - x + 4 y - 12 = 0

x^{2} + y^{2} - \frac{x}{4} + 2 y - 24 = 0

x^{2} + y^{2} - 4 x + 9 y + 18 = 0

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Amelia Discussed

Let P be the point on the parabola,

y^{2} = 8 x

which is at a minimum distance from the centre C of the circle,

x^{2} + (y + 6)^{2} = 1 .

Then the equation of the circle, passing through C and having its centre at P is :

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Question Text	Let P be the point on the parabola, $y^{2} = 8 x$ which is at a minimum distance from the centre C of the circle, $x^{2} + (y + 6)^{2} = 1 .$ Then the equation of the circle, passing through C and having its centre at P is :
Answer Type	Video solution: 1
Upvotes	150