Let $O$be the origin and let PQR be an arbitrary triangle. The point S is such that$\vec{O}P\dot{\vec{O}}Q+\vec{O}R\dot{\vec{O}}S=\vec{O}R\dot{\vec{O}}P+\vec{O}Q\dot{\vec{O}}S=\vec{O}Q$.$\vec{O}R+\vec{O}P\dot{\vec{O}}S$Then the triangle PQ has S as its:circumcentre (b) orthocentre (c) incentre (d) centroid

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