Let $n_1,\text{and}{n}_2$, be the number of red and black balls, respectively, in box I. Let $n_3\text{and}{n}_4$,be the number one red and b of red and black balls, respectively, in box II. One of the two boxes, box I and box II, was selected at random and a ball was drawn randomly out of this box. The ball was found to be red. If the probablity that this red ball was drawn from box II is $\frac{1}{3}$ then the correct option(s) with the possible values of $n_1,n_2,n_3,\text{and}{n}_4$, is(are)

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