Let i2=−1, then (i10−i111 )+(i11−i121 )+(i12−i131 )+(i13−i141 )+(i14+i151 ) is equal to

We know i2=−1(i10−i111 )+(i11−i121 )+(i12−i131 )+(i13−i141 )+(i14−i151 )=(i2−i31 )+(i3−i21 )+(i2−i1 )+(i−i21 )+(i2−i31 )=−1−−i1+(−i)−11+1−i1+i−−11+(−1)+−i1=−1+i1−i−1+1−i1+i+1−1−i1=−1−i1=−1+i=i−1

Get 2 FREE Instant-Explanations on Filo with code FILOAPP

Home

Let { i }^{ 2 }=-1, then ( { i }^{ 10 }- { 1 }{ { i }^{ 11 } }

Question

Let $i^{2} = - 1$ , then $(i^{10} - \frac{1}{i ^{11}}) + (i^{11} - \frac{1}{i ^{12}}) + (i^{12} - \frac{1}{i ^{13}}) + (i^{13} - \frac{1}{i ^{14}}) + (i^{14} + \frac{1}{i ^{15}})$ is equal to

- 1 + i

- 1 - i

1 + i

- i

i

Views: 527 students

Found 6 tutors discussing this question

Elizabeth Discussed

Let

i^{2} = - 1

, then

(i^{10} - \frac{1}{i ^{11}}) + (i^{11} - \frac{1}{i ^{12}}) + (i^{12} - \frac{1}{i ^{13}}) + (i^{13} - \frac{1}{i ^{14}}) + (i^{14} + \frac{1}{i ^{15}})

is equal to

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

We know

i^{2} = - 1

(i^{10} - \frac{1}{i ^{11}}) + (i^{11} - \frac{1}{i ^{12}}) + (i^{12} - \frac{1}{i ^{13}}) + (i^{13} - \frac{1}{i ^{14}}) + (i^{14} - \frac{1}{i ^{15}})

= (i^{2} - \frac{1}{i ^{3}}) + (i^{3} - \frac{1}{i ^{2}}) + (i^{2} - \frac{1}{i}) + (i - \frac{1}{i ^{2}}) + (i^{2} - \frac{1}{i ^{3}})

= - 1 - \frac{1}{- i} + (- i) - \frac{1}{1} + 1 - \frac{1}{i} + i - \frac{1}{- 1} + (- 1) + \frac{1}{- i}

= - 1 + \frac{1}{i} - i - 1 + 1 - \frac{1}{i} + i + 1 - 1 - \frac{1}{i}

= - 1 - \frac{1}{i} = - 1 + i = i - 1

Was this solution helpful?

150

Report

One destination for complete JEE/NEET preparation

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our maths tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	Let $i^{2} = - 1$ , then $(i^{10} - \frac{1}{i ^{11}}) + (i^{11} - \frac{1}{i ^{12}}) + (i^{12} - \frac{1}{i ^{13}}) + (i^{13} - \frac{1}{i ^{14}}) + (i^{14} + \frac{1}{i ^{15}})$ is equal to
Answer Type	Text solution:1
Upvotes	150

Let i2=−1, then (i10−i111​ )+(i11−i121​ )+(i12−i131​ )+(i13−i141​ )+(i14+i151​ ) is equal to

Text solutionVerified

Practice questions from similar books

Let $i^{2} = - 1$ , then $(i^{10} - \frac{1}{i ^{11}}) + (i^{11} - \frac{1}{i ^{12}}) + (i^{12} - \frac{1}{i ^{13}}) + (i^{13} - \frac{1}{i ^{14}}) + (i^{14} + \frac{1}{i ^{15}})$ is equal to