Let F(x)=∫xx2+6π[2cos2t.dt] for all x∈R and f:[0,21]→[0,∞) be a continuous function.For a∈[0,21], if F'(a)+2 is the area of the region bounded by x=0,y=0,y=f(x) and x=a, then f(0) is

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Let {F}{({x})}={_{{x}}^{{{x}^{{2}}+{}{{6}}}}}{[{2}{{}^{{2}}{t}

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Let $F (x) = \int_{x}^{x^{2} + \frac{π}{6}} [2 cos^{2} t . d t]$ for all $x \in R$ and $f : [0, \frac{1}{2}] \to [0, \infty)$ be a continuous function.For $a \in [0, \frac{1}{2}]$ , if F'(a)+2 is the area of the region bounded by x=0,y=0,y=f(x) and x=a, then f(0) is

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Let

F (x) = \int_{x}^{x^{2} + \frac{π}{6}} [2 cos^{2} t . d t]

for all

x \in R

and

f : [0, \frac{1}{2}] \to [0, \infty)

be a continuous function.For

a \in [0, \frac{1}{2}]

, if F'(a)+2 is the area of the region bounded by x=0,y=0,y=f(x) and x=a, then f(0) is

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Question Text	Let $F (x) = \int_{x}^{x^{2} + \frac{π}{6}} [2 cos^{2} t . d t]$ for all $x \in R$ and $f : [0, \frac{1}{2}] \to [0, \infty)$ be a continuous function.For $a \in [0, \frac{1}{2}]$ , if F'(a)+2 is the area of the region bounded by x=0,y=0,y=f(x) and x=a, then f(0) is
Answer Type	Video solution: 1
Upvotes	150