Let $f\left(x\right)=7{\tan }^{8}x+7{\tan }^{6}x-3{\tan }^{4}x-3{\tan }^{2}x$for all $x\in \left(-\frac{\pi }{2},\frac{\pi }{2}\right)$ . Then the correct expression (s) is (are) (a) ${\int }_0^{\frac{\pi }{4}}xf\left(x\right)dx=\frac{1}{12}$ (b)${\int }_0^{\frac{\pi }{4}}f\left(x\right)dx=0$(c)${\int }_0^{\frac{\pi }{4}}xf\left(x\right)=\frac{1}{6}$ (d) ${\int }_0^{\frac{\pi }{4}}f\left(x\right)dx=\frac{1}{12}$

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