[2−z1z2z1−2z2]=1 and ∣z2∣=1 then the value of ∣z1∣ is

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[{z_{1}-2z_{2}}{2-z_{1}z_{2}}]=1 and |z_{2}| 1 then the value

Question

$[\frac{z _{1} - 2 z _{2}}{2 - z _{1} z _{2}}] = 1$ and $∣ z_{2} ∣ \neq = 1$ then the value of $∣ z_{1} ∣$ is

4

2

1

\frac{1}{2}

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Amelia Discussed

[\frac{z _{1} - 2 z _{2}}{2 - z _{1} z _{2}}] = 1

and

∣ z_{2} ∣ \neq = 1

then the value of

∣ z_{1} ∣

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Question Text

[\frac{z _{1} - 2 z _{2}}{2 - z _{1} z _{2}}] = 1

and

∣ z_{2} ∣ \neq = 1

then the value of

∣ z_{1} ∣