In this section we shall find the sum of certain series of simple trigonometric which are in AP
$sin α + sin (α + β) + sin (α + 2 β) + ...... + sin [α + (n - 1) β] = sin [α + (\frac{( n - 1 )}{2}) β] sin \frac{n β}{2} / sin β /2$

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In this section we shall find the sum of certain series of simple trigonometric which are in AP

sin α + sin (α + β) + sin (α + 2 β) + ...... + sin [α + (n - 1) β] = sin [α + (\frac{( n - 1 )}{2}) β] sin \frac{n β}{2} / sin β /2

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Question Text

In this section we shall find the sum of certain series of simple trigonometric which are in AP

sin α + sin (α + β) + sin (α + 2 β) + ...... + sin [α + (n - 1) β] = sin [α + (\frac{( n - 1 )}{2}) β] sin \frac{n β}{2} / sin β /2

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