In the diagram as shown, a circle is drawn with centre $C\left(1,1\right)$ and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals $\theta$ where $0<\theta <\frac{\pi }{2}$.
Area of triangle OPR when $\theta =\pi /4$ is

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