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If z = 1 + i, then the multiplicative inverse of z^2 is (where

Question

If $z = 1 + i$ , then the multiplicative inverse of $z^{2}$ is (where $i = - 1$ )

2 i

1 - i

\frac{- i}{2}

3 i

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Daniel Discussed

z = 1 + i

, then the multiplicative inverse of

z^{2}

is (where

i = - 1

)

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

Given

z = 1 + i

Now,

z^{2} = 1 + 2 i + i^{2} = 2 i

[ Since

i^{2} = - 1

Now inverse of

z

\frac{1}{z} = \frac{1}{2 i} = - \frac{i}{2}

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Question Text	If $z = 1 + i$ , then the multiplicative inverse of $z^{2}$ is (where $i = - 1$ )
Answer Type	Text solution:1
Upvotes	150