If x=sin−1K, y=cos−1K, −1≤K≤1, then the correct relationship is-

x=sin−1K,y=cos−1K ∵sin−1θ +cos−1θ =2π ∴x+y=sin−1K+cos−1K=2π

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If x= ^{ -1 }{ K } , y= ^{ -1 }{ K } , -1 K 1, then the correc

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If $x = sin^{- 1} K$ , $y = cos^{- 1} K$ , $- 1 \leq K \leq 1$ , then the correct relationship is-

x + y = 2

x - y = 2

x + y = \frac{π}{2}

x - y = \frac{π}{2}

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Evelyn Discussed

x = sin^{- 1} K

y = cos^{- 1} K

- 1 \leq K \leq 1

, then the correct relationship is-

7 mins ago

Discuss this question LIVE

7 mins ago

x = sin^{- 1} K, y = cos^{- 1} K

∵ sin^{- 1} θ + cos^{- 1} θ = \frac{π}{2}

∴ x + y = sin^{- 1} K + cos^{- 1} K = \frac{π}{2}

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Question Text	If $x = sin^{- 1} K$ , $y = cos^{- 1} K$ , $- 1 \leq K \leq 1$ , then the correct relationship is-
Answer Type	Text solution:1
Upvotes	151