If X={4n−3n−1:n∈N}andY={9(n−1):n∈N}, where N is the set of natural numbers, then X∪Yis equal to

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If {X}{}={}{{4}^{{n}}-{3}{n}-{1}{}:{}{n}{N}}{}{a}{n}{d}{}{Y}{}

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If $X = {4^{n} - 3 n - 1 : n \in N} a n d Y = {9 (n - 1) : n \in N}$ , where N is the set of natural numbers, then $X \cup Y$ is equal to

Y - X

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Jack Discussed

X = {4^{n} - 3 n - 1 : n \in N} a n d Y = {9 (n - 1) : n \in N}

, where N is the set of natural numbers, then

X \cup Y

is equal to

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Question Text	If $X = {4^{n} - 3 n - 1 : n \in N} a n d Y = {9 (n - 1) : n \in N}$ , where N is the set of natural numbers, then $X \cup Y$ is equal to
Answer Type	Video solution: 1
Upvotes	150