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If x < 0, y < 0 such that xy = 1, then write the value of ^{-1

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If $x < 0, y < 0$ such that $x y = 1$ , then write the value of $tan^{- 1} x + tan^{- 1} y$ .

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x < 0, y < 0

such that

x y = 1

, then write the value of

tan^{- 1} x + tan^{- 1} y

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

tan^{- 1} x + tan^{- 1} y

= tan^{- 1} (\frac{x + y}{1 - x y})

= tan^{- 1} (\frac{x + y}{1 - 1})

given

x y = 1

= tan^{- 1} (\frac{x + y}{0})

= tan^{- 1} (\infty)

= \frac{π}{2}

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Question Text	If $x < 0, y < 0$ such that $x y = 1$ , then write the value of $tan^{- 1} x + tan^{- 1} y$ .
Answer Type	Text solution:1
Upvotes	150