If the curve y=ax1/2+bx passes through the point (1,2) and lies above the x-axis for 0≤x≤9 and the area enclosed by the curve, the x-axis, and the line x=4 is 8 sq. units. Then
Connecting you to a tutor in 60 seconds.
Get answers to your doubts.
Two curves C1≡[f(y)]2/3+[f(x)]1/3=0andC2≡[f(y)]2/3+[f(x)]2/3=12, satisfying the relation (x−y)f(x+y)−(x+y)f(x−y)=4xy(x2−y2) The area bounded by C1andC2 is
A curve y = f(x) is such that f(x)≥0andf(0)=0 and bounds a curvilinear triangle with the base [0,x] whose area is proportional to (n+1)th power of f(x)⋅ If f(1)=1 then find f(x).
If S is the sum of cubes of possible value of c for which the area of the figure bounded by the curve y=8x2−x5, then straight lines x=1 and x=c and the abscissa axis is equal to 16/3, then the value of [S], where [.] denotes the greatest integer function, is ___.
The area of the closed figure bounded by y=2x2−2x+2 and the tangents to it at (1,1/2) and (4,2) is
Area of region bounded by the curve y=416−x2 and y=sec−1[−sin2x] (where [x] denotes the greatest ingeger function) is
Find the area bounded by the curve x2=y,x2=−y,andy2=4x−3.
Consider curves y=x21,y=4(x−1)1. Let α be the value of a(a>2) for which area bounded by curves between x=2andx=a is 1/a is e2+1andβ be the of b∈(1,2), for which the area bounded by curves between x=b and x=2 is 1−b1, then
Find the area of the region enclosed by y=−5x−x2andy=x on interval [−1,5]