If tan−1(x−1x+1)+tan−1(xx−1)=π+tan−1(−7), then x=

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If ^{-1}({x+1}{x-1})+^{-1}({x-1}{x})= +^{-1}(-7), then x=

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If $tan^{- 1} (\frac{x + 1}{x - 1}) + tan^{- 1} (\frac{x - 1}{x}) = π + tan^{- 1} (- 7)$ , then $x =$

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tan^{- 1} (\frac{x + 1}{x - 1}) + tan^{- 1} (\frac{x - 1}{x}) = π + tan^{- 1} (- 7)

, then

x =

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Question Text

tan^{- 1} (\frac{x + 1}{x - 1}) + tan^{- 1} (\frac{x - 1}{x}) = π + tan^{- 1} (- 7)

, then

x =