If ratio of the roots of the quadratic equation $3m^2{x}^2+m\left(m-4\right)x+2=0$ is $\lambda$ such that $\lambda +\frac{1}{\lambda }=1$ then least value of $m$ is (A) $-2-2\sqrt{3}$ (B) $-2+2\sqrt{3}$ (C) $4+3\sqrt{2}$ (D) $4-3\sqrt{2}$

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