If I=∫((sinx)n+1cosx(sinx)n−sinxn1)dx is eqaul to (a) (n2−1n)(1−sinxn−11)n1+1+c (b) (n2+1n)(1−sinxn−11)n1+1+c (c) (n2+1n)(1−sinxn−11)n1+c (d) (n2−1n)(1−sinx1)n1+1+c

Click here to view the solution.

Get 2 FREE Instant-Explanations on Filo with code FILOAPP

If {I}={({{{({{{x}}})}^{{n}}-{{{x}}}^{{{{1}}{{n}}}}}}{{{({{{x}

Question

If $I = \int (\frac{( sin x ) ^{n} - sin x ^{\frac{1}{n}}}{( sin x ) ^{n + 1} cos x}) d x$ is eqaul to (a) $(\frac{n}{n ^{2} - 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n} + 1} + c$ (b) $(\frac{n}{n ^{2} + 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n} + 1} + c$ (c) $(\frac{n}{n ^{2} + 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n}} + c$ (d) $(\frac{n}{n ^{2} - 1}) (1 - \frac{1}{sin x})^{\frac{1}{n} + 1} + c$

Views: 786 students

Found 7 tutors discussing this question

Henry Discussed

I = \int (\frac{( sin x ) ^{n} - sin x ^{\frac{1}{n}}}{( sin x ) ^{n + 1} cos x}) d x

is eqaul to (a)

(\frac{n}{n ^{2} - 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n} + 1} + c

(b)

(\frac{n}{n ^{2} + 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n} + 1} + c

(c)

(\frac{n}{n ^{2} + 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n}} + c

(d)

(\frac{n}{n ^{2} - 1}) (1 - \frac{1}{sin x})^{\frac{1}{n} + 1} + c

14 mins ago

Discuss this question LIVE

14 mins ago

Question Text

I = \int (\frac{( sin x ) ^{n} - sin x ^{\frac{1}{n}}}{( sin x ) ^{n + 1} cos x}) d x

is eqaul to (a)

(\frac{n}{n ^{2} - 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n} + 1} + c

(b)

(\frac{n}{n ^{2} + 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n} + 1} + c

(c)

(\frac{n}{n ^{2} + 1}) (1 - \frac{1}{sin x ^{n - 1}})^{\frac{1}{n}} + c

(d)

(\frac{n}{n ^{2} - 1}) (1 - \frac{1}{sin x})^{\frac{1}{n} + 1} + c