If f(x)={sinx2x=nπ and n∈I2x=nπ and g(x)=⎩⎨⎧x2+145x=0x=0x=2 then x→0limg{f(x)} is

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If $f (x) = {sin x 2 x \neq = n π and n \in I_{2} x = n π$ and $g (x) = ⎩ ⎨ ⎧ x^{2} + 1 45 x \neq = 0 x = 0 x = 2$ then $x \to 0 lim g {f (x)}$ is

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f (x) = {sin x 2 x \neq = n π and n \in I_{2} x = n π

and

g (x) = ⎩ ⎨ ⎧ x^{2} + 1 45 x \neq = 0 x = 0 x = 2

then

x \to 0 lim g {f (x)}

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Question Text

f (x) = {sin x 2 x \neq = n π and n \in I_{2} x = n π

and

g (x) = ⎩ ⎨ ⎧ x^{2} + 1 45 x \neq = 0 x = 0 x = 2

then

x \to 0 lim g {f (x)}