If f(x)=2tan^{-1}x+sin^{-1}\left (\dfrac {2x}{1+x^2}\right ) then for x>1, f(x)=

Name: If f(x)=2tan^{-1}x+sin^{-1}\left (\dfrac {2x}{1+x^2}\right ) then for x>1, f(x)=
Uploaded: 2021-01-01T18:41:02.000Z
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Description: If f(x)=2tan^{-1}x+sin^{-1}\left (\dfrac {2x}{1+x^2}\right ) then for x>1, f(x)=

If f(x)=2tan^{-1}x+sin^{-1}\left (\dfrac {2x}{1+x^2}\right ) then

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Class 12 Maths Calculus Inverse Trigonometric Functions

500

150

f (x) = 2 t a n^{- 1} x + s i n^{- 1} (\frac{2 x}{1 + x ^{2}})

then for x>1, f(x)=

(a)

s e c^{- 1} x

(b)

s i n^{- 1} x

(c)

π

(d)

\frac{π}{2}

Correct answer: (a)

500

150

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Related Questions

Solve:

\frac{sin ^{- 1} x - cos ^{- 1} x}{sin ^{- 1} x - cos ^{- 1} x}, x ϵ [0, 1]

Find the value of x which satisfy the equation

s i n^{- 1} x + s i n^{- 1} (1 - x) = c o s^{- 1} x

Prove that :

cos^{- 1} (\frac{1 2}{1 3}) + sin^{- 1} (\frac{3}{5}) = sin^{- 1} (\frac{5 6}{6 5})

Solve the following equation

sec^{- 1} (\frac{x}{a}) - sec^{- 1} (\frac{x}{b}) = sec^{- 1} b - sec^{- 1} a

tan^{- 1} (tan \frac{5 π}{4}) = α

and

tan^{- 1} (- tan \frac{2 π}{3}) = β

then.

Simplify:

t a n^{- 1} (1 / 2) + t a n^{- 1} (1 / 3) .

The value of sin

(2 sin^{- 1} 0.8)

is equal to.

Number of triplets

(x, y, z)

satisfying

sin^{- 1} x + sin^{- 1} y + cos^{- 1} z = 2 π