If An is the area bounded by y=xandy=xn,n∈N,thenA2A˙3An= n(n+1)1 (b) 2∩(n+1)1 2n−1n(n+1)1 (d) 2n−2n(n+1)1

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If {A}_{{n}} is the area bounded by {y}={x}{a}{n}{.{d}{y}.}={x

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If $A_{n}$ is the area bounded by $y = x a n d y = x^{n}, n \in N, t h e n A_{2} \dot{A}_{3} A_{n} =$ $\frac{1}{n ( n + 1 )}$ (b) $\frac{1}{2 ^{\cap} ( n + 1 )}$ $\frac{1}{2 ^{n - 1} n ( n + 1 )}$ (d) $\frac{1}{2 ^{n - 2} n ( n + 1 )}$

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A_{n}

is the area bounded by

y = x a n d y = x^{n}, n \in N, t h e n A_{2} \dot{A}_{3} A_{n} =

\frac{1}{n ( n + 1 )}

(b)

\frac{1}{2 ^{\cap} ( n + 1 )}

\frac{1}{2 ^{n - 1} n ( n + 1 )}

(d)

\frac{1}{2 ^{n - 2} n ( n + 1 )}

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Question Text

A_{n}

is the area bounded by

y = x a n d y = x^{n}, n \in N, t h e n A_{2} \dot{A}_{3} A_{n} =

\frac{1}{n ( n + 1 )}

(b)

\frac{1}{2 ^{\cap} ( n + 1 )}

\frac{1}{2 ^{n - 1} n ( n + 1 )}

(d)

\frac{1}{2 ^{n - 2} n ( n + 1 )}