If a=101(3i^+k^)andb=71(2i^+3j^−6k^),then the value of (2a−b)(a×b)×(a+2b)˙ is:

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If {a}={{1}}{{{{{10}}}}}{({3}{{i}}+{{k}})}{and}{{b}}={{1}}{{7}

Question

If $a = \frac{1}{10} (3 \hat{i} + \hat{k}) and b = \frac{1}{7} (2 \hat{i} + 3 \hat{j} - 6 \hat{k}),$ then the value of $(2 a - b) \dot{(a \times b) \times (a + 2 b)}$ is:

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Oliver Discussed

a = \frac{1}{10} (3 \hat{i} + \hat{k}) and b = \frac{1}{7} (2 \hat{i} + 3 \hat{j} - 6 \hat{k}),

then the value of

(2 a - b) \dot{(a \times b) \times (a + 2 b)}

is:

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Question Text	If $a = \frac{1}{10} (3 \hat{i} + \hat{k}) and b = \frac{1}{7} (2 \hat{i} + 3 \hat{j} - 6 \hat{k}),$ then the value of $(2 a - b) \dot{(a \times b) \times (a + 2 b)}$ is:
Answer Type	Video solution: 1
Upvotes	151