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From the set of numbers 1 to 11 two number are taken such that

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From the set of numbers 1 to 11 two number are taken such that their sum is eve, then the conditional probability that selected numbers are even is equal to (A) $\frac{3}{7}$ (B) $\frac{3}{5}$ (C) $\frac{5}{7}$ (D) $\frac{2}{5}$

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From the set of numbers 1 to 11 two number are taken such that their sum is eve, then the conditional probability that selected numbers are even is equal to (A)

\frac{3}{7}

(B)

\frac{3}{5}

(C)

\frac{5}{7}

(D)

\frac{2}{5}

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Question Text	From the set of numbers 1 to 11 two number are taken such that their sum is eve, then the conditional probability that selected numbers are even is equal to (A) $\frac{3}{7}$ (B) $\frac{3}{5}$ (C) $\frac{5}{7}$ (D) $\frac{2}{5}$
Answer Type	Video solution: 1
Upvotes	150

From the set of numbers 1 to 11 two number are taken such that their sum is eve, then the conditional probability that selected numbers are even is equal to (A) 73​ (B) 53​ (C) 75​ (D) 52​

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From the set of numbers 1 to 11 two number are taken such that their sum is eve, then the conditional probability that selected numbers are even is equal to (A) $\frac{3}{7}$ (B) $\frac{3}{5}$ (C) $\frac{5}{7}$ (D) $\frac{2}{5}$